Multiplying the number of moles of H A 2 SO A 4 by this factor gives us the number of moles of NaOH needed: 3.16 × 10 − 2 mol H 2 SO 4 × 2 mol NaOH 1 mol H 2 SO 4 = 6.32 × 10 − 2 mol NaOH. Notice how we wrote the mole ratio so that the moles of H A 2 SO A 4 cancel out, resulting in moles of NaOH as the final units.
Word Equation. Sodium Hydroxide + Nitric Acid = Sodium Nitrate + Water. NaOH + HNO3 = NaNO3 + H2O is a Double Displacement (Metathesis) reaction where one mole of aqueous Sodium Hydroxide [NaOH] and one mole of aqueous Nitric Acid [HNO 3] react to form one mole of aqueous Sodium Nitrate [NaNO 3] and one mole of liquid Water [H 2 O] ShowStep 4: Substitute Coefficients and Verify Result. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. 12 (NH4)2MoO4 + Na3PO4 + 3 HNO3 = (NH4)3P (Mo3O10)4 + 12 H2O + 3 NaNO3 + 21 NH3. Reactants. Products.
In this video we'll balance the equation HNO3 + Na = NaNO3 + H2 and provide the correct coefficients for each compound.This reaction most likely doesn't give .